A marathon runner runs a distance of 42 km at a uniform speed of 12 km/h. What is the time taken to finish the race? MCQ with Answer and Explanation
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Question #1
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A man walks at a speed of 6 km/h instead of 5 km/h and thereby covers 12 km more in the same duration. Find the actual distance covered by him at his normal speed.
Correct Answer: Option A
Explanation:
Let duration be t hours. Distance difference = 6t - 5t = t = 12 hours. Distance at normal speed (5 km/h) = 5 * 12 = 60 km.
Let duration be t hours. Distance difference = 6t - 5t = t = 12 hours. Distance at normal speed (5 km/h) = 5 * 12 = 60 km.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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The speeds of two cars are in the ratio 4 : 3. If they cover the same distance, and the slower car takes 2 hours, how much time does the faster car take?
Correct Answer: Option D
Explanation:
Ratio of speeds = 4:3, so ratio of times taken = 3:4. The slower car corresponds to 4 parts = 2 hours => 1 part = 0.5 hours. Time for the faster car = 3 parts = 3 * 0.5 = 1.5 hours.
Ratio of speeds = 4:3, so ratio of times taken = 3:4. The slower car corresponds to 4 parts = 2 hours => 1 part = 0.5 hours. Time for the faster car = 3 parts = 3 * 0.5 = 1.5 hours.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A thief escapes at 2:00 PM at a speed of 40 km/h. The owner follows him at 3:30 PM at a speed of 50 km/h. At what time will the owner catch the thief?
Correct Answer: Option D
Explanation:
By 3:30 PM, the thief has run for 1.5 hours and covered 40 * 1.5 = 60 km. Relative speed = 50 - 40 = 10 km/h. Time taken to catch = 60 / 10 = 6 hours. Catching time = 3:30 PM + 6 hours = 9:30 PM.
By 3:30 PM, the thief has run for 1.5 hours and covered 40 * 1.5 = 60 km. Relative speed = 50 - 40 = 10 km/h. Time taken to catch = 60 / 10 = 6 hours. Catching time = 3:30 PM + 6 hours = 9:30 PM.
This question belongs to:
Maths
Time Speed and Distance
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