A sedan covers a distance path of 480 km at a uniform tracking speed. If the speed index is lowered by 10 km/h, the trip records 2 hours longer. Find the original baseline speed. MCQ with Answer and Explanation
A sedan covers a distance path of 480 km at a uniform tracking speed. If the speed index is lowered by 10 km/h, the trip records 2 hours longer. Find the original baseline speed.
A. 50 km/h
B. 45 km/h
C. 60 km/h
D. 55 km/h
Answer: Option A
Solution (By JKExamLibrary)
Let original speed be s. 480 / (s - 10) - 480 / s = 2 => 240 / (s - 10) - 240 / s = 1 => 2400 = s(s - 10). Solving s^2 - 10s - 2400 = 0 gives (s - 50)(s + 40) = 0. Baseline speed = 50 km/h.
A thief is spotted by a policeman from a distance of 250 meters. When the policeman starts the chase, the thief also starts running. Assuming the speed of the thief to be 10 km/h and that of the policeman to be 12 km/h, how far will the thief have run before he is overtaken?
Explanation:
Relative speed = 12 - 10 = 2 km/h. Time taken to catch the thief = 0.25 km / 2 km/h = 1/8 hour. Distance run by the thief = Speed * Time = 10 km/h * (1/8) hour = 1.25 km = 1250 meters.
Explanation:
When A covers 200m, B covers 180m and C covers 162m. This means in a match distance where B covers 180 meters, C covers 162 meters. Scaling down to 90 meters: B covers 90m, C covers 162 * (90/180) = 81m. Therefore, B beats C by 90 - 81 = 9 meters.
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