In a 200-meter sprint, X beats Y by 20 meters and Y beats Z by 10 meters. By how many meters does X beat Z in the same race? MCQ with Answer and Explanation
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Question #1
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A man leaves point A at 6 AM at a speed of 4 km/h. Another man leaves point A from the same direction at 8 AM at a speed of 6 km/h. At what distance from point A will they meet?
Correct Answer: Option B
Explanation:
By 8 AM, the first man has traveled for 2 hours, covering 4 * 2 = 8 km. Relative speed = 6 - 4 = 2 km/h. Time taken to meet = 8 / 2 = 4 hours. Distance from A = Speed of second man * Time = 6 * 4 = 24 km.
By 8 AM, the first man has traveled for 2 hours, covering 4 * 2 = 8 km. Relative speed = 6 - 4 = 2 km/h. Time taken to meet = 8 / 2 = 4 hours. Distance from A = Speed of second man * Time = 6 * 4 = 24 km.
This question belongs to:
Maths
Time Speed and Distance
Question #2
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A train running at 72 km/h passes a tunnel 300 meters long in 25 seconds. Find the length of the train.
Correct Answer: Option B
Explanation:
Speed = 72 * (5/18) = 20 m/s. Total distance in 25 seconds = 20 * 25 = 500 meters. Length of train = 500 - 300 = 200 meters.
Speed = 72 * (5/18) = 20 m/s. Total distance in 25 seconds = 20 * 25 = 500 meters. Length of train = 500 - 300 = 200 meters.
This question belongs to:
Maths
Time Speed and Distance
Question #3
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A field clerk walking at 5 km/h handles a regular sector. If he steps up to run at 10 km/h, he takes 24 minutes less across the course stretch. Find the absolute distance profile.
Correct Answer: Option A
Explanation:
Time difference = 24 minutes = 24/60 = 2/5 hours. Let distance be d. d / 5 - d / 10 = 2/5 => d / 10 = 2/5 => d = 4 km.
Time difference = 24 minutes = 24/60 = 2/5 hours. Let distance be d. d / 5 - d / 10 = 2/5 => d / 10 = 2/5 => d = 4 km.
This question belongs to:
Maths
Time Speed and Distance
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