The equivalent weight of KMnO4 in an acidic medium is:
A. M/5
B. M/1
C. M/7
D. M/3
Answer: Option A
Solution (By JKExamLibrary)
In an acidic medium, potassium permanganate (KMnO4) is reduced to Mn2+. The oxidation state of Mn changes from +7 to +2, a change of 5. The equivalent weight of an oxidizing agent is its molar mass (M) divided by the number of electrons gained per molecule. Thus, Equivalent weight = M/5.
Explanation:
Calgon is the trade name for sodium hexametaphosphate (Na6P6O18). It is used to soften hard water because the hexametaphosphate ion binds (chelates) with calcium and magnesium ions in the water, forming a soluble complex. This prevents the metal ions from interfering with soap lathering.
Explanation:
Ideal gas assumptions: particles have negligible volume, no intermolecular forces, and elastic collisions. Real gases deviate due to finite molecular size and attractions. At high pressure and low temperature, real gases deviate significantly; van der Waals equation corrects. So having strong attractive forces is not an ideal gas property. Ideal gas law PV = nRT is a limiting law.
Explanation:
Oxidation is defined as loss of electrons, increase in oxidation number, or loss of hydrogen / gain of oxygen. Reduction is gain of electrons. Oxidation does not always require oxygen; for example, 2Na + Cl₂ → 2NaCl involves oxidation of Na without oxygen.
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