Walking at 3/5 of his normal speed, a person is 20 minutes late to his destination. What is his normal time?
A. 30 minutes
B. 40 minutes
C. 25 minutes
D. 35 minutes
Answer: Option A
Solution (By JKExamLibrary)
New speed = 3/5 of normal speed => New time = 5/3 of normal time. Difference = 2/3 of normal time = 20 minutes. Normal time = (20 * 3) / 2 = 30 minutes.
A man leaves point A at 6 AM at a speed of 4 km/h. Another man leaves point A from the same direction at 8 AM at a speed of 6 km/h. At what distance from point A will they meet?
Explanation:
By 8 AM, the first man has traveled for 2 hours, covering 4 * 2 = 8 km. Relative speed = 6 - 4 = 2 km/h. Time taken to meet = 8 / 2 = 4 hours. Distance from A = Speed of second man * Time = 6 * 4 = 24 km.
A vehicle covers a specific highway distance at 50 km/h. If it spikes its speed to 60 km/h, it clears the stretch 20 minutes early. Find the total distance.
Explanation:
Time difference = 20 minutes = 20/60 = 1/3 hours. Let distance be d. d / 50 - d / 60 = 1/3 => (6d - 5d) / 300 = 1/3 => d / 300 = 1/3 => d = 100 km.
The speed of a train is 20% more than the speed of a car. Both start from city P at the same time and reach city Q, 120 km away, at the same time. On the way, the train stops for 10 minutes at various stations. What is the speed of the car?
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