Walking at 3/5 of his normal speed, a person is 20 minutes late to his destination. What is his normal time? MCQ with Answer and Explanation

Walking at 3/5 of his normal speed, a person is 20 minutes late to his destination. What is his normal time?
A. 30 minutes
B. 40 minutes
C. 25 minutes
D. 35 minutes
Answer: Option A
Solution (By JKExamLibrary)
New speed = 3/5 of normal speed => New time = 5/3 of normal time. Difference = 2/3 of normal time = 20 minutes. Normal time = (20 * 3) / 2 = 30 minutes.

This question belongs to: Maths Time Speed and Distance

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Practice More Time Speed and Distance Questions

Question #1 Report Error
A man leaves point A at 6 AM at a speed of 4 km/h. Another man leaves point A from the same direction at 8 AM at a speed of 6 km/h. At what distance from point A will they meet?
A. 28 km
B. 32 km
C. 20 km
D. 24 km

Correct Answer: Option D


Explanation:
By 8 AM, the first man has traveled for 2 hours, covering 4 * 2 = 8 km. Relative speed = 6 - 4 = 2 km/h. Time taken to meet = 8 / 2 = 4 hours. Distance from A = Speed of second man * Time = 6 * 4 = 24 km.

This question belongs to: Maths Time Speed and Distance
Question #2 Report Error
A vehicle covers a specific highway distance at 50 km/h. If it spikes its speed to 60 km/h, it clears the stretch 20 minutes early. Find the total distance.
A. 120 km
B. 90 km
C. 110 km
D. 100 km

Correct Answer: Option D


Explanation:
Time difference = 20 minutes = 20/60 = 1/3 hours. Let distance be d. d / 50 - d / 60 = 1/3 => (6d - 5d) / 300 = 1/3 => d / 300 = 1/3 => d = 100 km.

This question belongs to: Maths Time Speed and Distance
Question #3 Report Error
The speed of a train is 20% more than the speed of a car. Both start from city P at the same time and reach city Q, 120 km away, at the same time. On the way, the train stops for 10 minutes at various stations. What is the speed of the car?
A. 100 km/h
B. 150 km/h
C. 140 km/h
D. 120 km/h

Correct Answer: Option D


Explanation:
Let car speed be c, then train speed is 1.2c. Time difference = 120/c - 120/(1.2c) = 10/60 hour = 1/6 hour. 120/c * (1 - 1/1.2) = 1/6 => 120/c * (0.2/1.2) = 1/6 => 120/c * (1/6) = 1/6 => c = 120 km/h.

This question belongs to: Maths Time Speed and Distance