Which of the following isotopes is used in the treatment of blood cancers? MCQ with Answer and Explanation

Which of the following isotopes is used in the treatment of blood cancers?
A. Sodium-24
B. Iodine-131
C. Carbon-14
D. Cobalt-60
Answer: Option D
Solution (By JKExamLibrary)
Cobalt-60 is a radioactive isotope that emits strong gamma radiation. It is widely used in radiotherapy to treat various types of cancers, including blood cancers like leukemia. Iodine-131 is used for thyroid disorders, Carbon-14 for radiocarbon dating, and Sodium-24 for detecting blood clots.

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Question #1
The compound formed by transfer of electrons from a metal to a non-metal is:
A. Cl₂
B. H₂O
C. CO₂
D. KBr

Correct Answer: Option D


Explanation:
KBr is ionic; potassium (metal) transfers one electron to bromine (non-metal) forming K⁺ and Br⁻. CO₂ and H₂O are covalent (sharing). Cl₂ is covalent (nonpolar).

This question belongs to: Science chemistry
Question #2
Electrolysis is a process in which:
A. Electrical energy is used to cause a non-spontaneous chemical reaction
B. Chemical energy is converted to electrical energy
C. Heat energy is converted to electrical energy
D. Light energy is absorbed

Correct Answer: Option A


Explanation:
Electrolysis uses an external electric current to drive a chemical reaction that would not occur spontaneously. Example: 2NaCl (molten) → 2Na + Cl₂. Option A describes a galvanic cell. Electrolytic cells require energy input. Electroplating, extraction of reactive metals (Al, Na), and production of chemicals (NaOH, Cl₂) rely on electrolysis.

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Question #3
The neutron was discovered by James Chadwick in 1932 by bombarding which element with alpha particles?
A. Lead
B. Gold
C. Uranium
D. Beryllium

Correct Answer: Option D


Explanation:
Chadwick bombarded beryllium (Be) with alpha particles from polonium, producing a highly penetrating neutral radiation, which he identified as neutrons: ⁹Be + ⁴He → ¹²C + ¹n. Gold was used by Rutherford for nucleus discovery. Uranium for fission. Lead for shielding.

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